關於Quadratic function

2009-12-07 4:05 am


1.




x


30


40


55


70


75


80




y


219


249


238


163


127


87




2.




x


35


40


55


65


70


75




y


294


308


294


239


201


156




3.




x


30


40


55


70


75


80




y


327


37


355


243


189


129




以上三條Function是甚麼? 以y=a(x-h)^2+k表示.謝謝大家的回答. ^^

回答 (2)

2009-12-08 7:51 am
✔ 最佳答案
Your provided data do not exactly match quadratic equations. A relative easy way is to approximate the quadratic equations by plotting the data on a graph.
(1) http://img215.imageshack.us/img215/2840/graph1g.png

圖片參考:http://img215.imageshack.us/img215/2840/graph1g.png

The graph indicate a maximum of about 250.5 at x = 45. At x = 80, y is about 87
My estimation is y = a(x – 45)^2 + 250.5
Sub (80,87) into equation yields a = -0.133
Therefore y = -0.133(x – 45)^2 + 250.5
The result obtained by Excel quadratic curve fitting is
y = 0.1352(x – 44.96)^2 + 250.6
(2) http://img245.imageshack.us/img245/7848/graph2c.png

圖片參考:http://img245.imageshack.us/img245/7848/graph2c.png

The graph indicate a maximum of about 311 at x = 44.5. At x = 75, y is about 154
My estimation is y = a(x – 44.5)^2 + 311
Sub (75,154) into equation yields a = -0.169
Therefore y = -0.169(x – 44.5)^2 + 311
The result obtained by Excel quadratic curve fitting is
y = 0.1699(x – 44.67)^2 + 310.7
(3) http://img187.imageshack.us/img187/3365/graph3.png

圖片參考:http://img187.imageshack.us/img187/3365/graph3.png

The graph indicate a maximum of about 374 at x = 45. At x = 80, y is about 126
My estimation is y = a(x – 45)^2 + 374
Sub (80,126) into equation yields a = -0.202
Therefore y = -0.202(x – 45)^2 + 374
The result obtained by Excel quadratic curve fitting is
y = 0.2015(x – 44.94)^2 + 373.4
2009-12-07 4:08 am
1 y=a(x-h)^2+k

2 y=a(x-h)^2+k

3 y=a(x-h)^2+k


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