展開下列各式，需詳細列明步驟。
1. (2s-3)4s
2. (2y-5)(y+7)
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中一數學 急
2009-12-04 5:24 am
回答 (7)
2009-12-04 5:30 am
✔ 最佳答案
1. (2s-3)4s=4s(2s)-4s(3)
=8s2-12s
2. (2y-5)(y+7)
=2y2+14y-5y-35
=2y2+9y-35
2009-12-04 7:25 am
(2s)(4s)-3(4s)
=8s^2-12s
(2y)(y)+7(2y)-5y-35
=2y^2+14y-5y-35
=2y^2+9y-35
=8s^2-12s
(2y)(y)+7(2y)-5y-35
=2y^2+14y-5y-35
=2y^2+9y-35
參考: myself
2009-12-04 6:59 am
(2s-3)4s
=8s^2-12s
(2y-5)(y+7)
=2y^2-5y+14y-35
=2y^2+9y-35
=8s^2-12s
(2y-5)(y+7)
=2y^2-5y+14y-35
=2y^2+9y-35
2009-12-04 6:08 am
1) 4s(2s-3)
=8s^2 - 12s
2) (2y-5)(y+7)
=2y(y+7) - 5(y+7)
=2y^2 + 14y -5y +35
=2y^2 + 9y + 35
=8s^2 - 12s
2) (2y-5)(y+7)
=2y(y+7) - 5(y+7)
=2y^2 + 14y -5y +35
=2y^2 + 9y + 35
參考: mine
2009-12-04 5:38 am
(2s-3)4s
=4s(2s)-4s(3)
=8s2-12s
(2y-5)(y+7)
=2y2+14y-5y-35
=2y2+9y-35
=4s(2s)-4s(3)
=8s2-12s
(2y-5)(y+7)
=2y2+14y-5y-35
=2y2+9y-35
2009-12-04 5:33 am
1. (2s-3)4s
=8s-12s
=-4s
2.(2y-5)(y+7)
=2y square+14y-5y-35
=2y square+9y-35
=8s-12s
=-4s
2.(2y-5)(y+7)
=2y square+14y-5y-35
=2y square+9y-35
2009-12-04 5:29 am
(2s-3)4s
=6s*2-12s
(2y-5)(y+7)
=2y*2-5y+14y-35
=2y*2+9y-35
2009-12-03 21:33:47 補充：
sorry!!
(2s-3)4s
=8s*2-12s
=6s*2-12s
(2y-5)(y+7)
=2y*2-5y+14y-35
=2y*2+9y-35
2009-12-03 21:33:47 補充：
sorry!!
(2s-3)4s
=8s*2-12s
收錄日期: 2021-04-23 20:42:16
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