how do you factor out x^3- 3x^2+4x-12?

x³- 3x²+4x-12

= x³ +4x -3x² -12

= x( x ² +4) -3 ( x ² +4)

= (x-3)( x ² +4 )

x - 3 is a factor

Find other factors by using synthetic division.

3 | 1______-3______4______-12
_ |________3______0_______12
_ | 1______0______4________0

( x - 3 ) ( x ² + 4 )

x^3- 3x^2+4x-12
=(x^3- 3x^2)+(4x-12)
=x^2(x-3)+4(x-3)
=(x^2+4)(x-3)

x^3 - 3x^2 + 4x - 12= (x^3 - 3x^2) + (4x - 12)
= x^2(x - 3) + 4(x - 3)
= (x - 3)(x^2 + 4)

you can use trial and error too

x^3 -3x^2+4x-12=(x^3-3x^2)+(4x-12) factorize by grouping
=x^2(x-3)+4(x-3) take (x-3) as common factor
=(x-3)(x^2+4)

It can be factored by grouping.
x³ – 3x² + 4x – 12 = (x³ – 3x²) + (4x – 12)
.......................... = x²(x – 3) + 4(x – 3)
.......................... = (x – 3)(x² + 4)

x^3 - 3x^2 + 4x - 12
= (x^3 - 3x^2) + (4x - 12)
= x^2(x - 3) + 4(x - 3)
= (x - 3)(x^2 + 4)

(x - 3 )(x ^2 + 4 )