簡單的一元一次方程,help me plz^^”

2009-11-29 10:32 pm
2(a+1)+3a=17
要步驟架=]]]
thz

回答 (5)

2009-11-30 1:28 am
✔ 最佳答案
2(a+1)+3a=17
2a+2x1+3a=17
5a+2=17
5a=17-2
5a=15
a=15/5
a = 3
2009-11-29 11:59 pm
2(a+1)+3a=17
2(1)+2a=17
2a=15
a=7.5

by ME!
2009-11-29 11:17 pm
2(a+1)+3a=17
2a+2+3a=17
5a+2=17
5a=15
a=3
2009-11-29 10:44 pm
2(a+1)+3a=17
2a+a+3a=17 <-- 先柝括號2(a+1) =2 x a + 2 x 1 = 2a+a
6a=17 <--移項
a=17/6,, 等如17除6

2009-11-29 16:11:47 補充:
2(a+1)+3a=17
2a+2+3a=17 <-- 先柝括號2(a+1) =2 x a + 2 x 1 = 2a+2
5a=15 <--移項
a=3,,
2009-11-29 10:39 pm
2(a+1)+3a=17
2a+2+3a=17
5a=17-2
5a/5=15/5
a=3
唔知正唔正確&gt;.&lt;


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