making me confusing.
In S.H.M ,some load is dropped into the object,the amplitude of S.H.M will
decrease.It can be proved by conservation of momentum.But if the
amplitude decrease,there are some energy lost,where are the energy
going?.My teacher tell me it may lose in form of sound energy when it was
dropped.But in my calculation,it is not related to the height of dropping.Even
i pull it lightly,by conservation of momentum, A will decrease.
Prove:
v1=initial max velocity. v2=final max velocity
m1v1=m2v2
A1=initial Amplitude A2=final Amplitude
Initial energy=0.5x k x A1=0.5 m1 v1^2
Final energy=0.5 x k x A2=0.5 m2 v2^2.
0.5 m2 v2 v2=Initial E x v2
As m2 increase,so v2 decrease.
So final energy is lower,so a2 is lower.
The energy is lost in form of?
更新1:
How to explain it if the energy is lost in form of heat even if i pull it lightly? Please explain it as detail,a full description to procedures of lossing energy.
