solve equation

√(2/3)^x = 9/4
log √(2/3)^x = log (9/4)

x*log (2/3) = log (9/4)

x = [log (2/3) / log (9/4)]

=-4

2009-11-27 19:53:31 補充：
上面亂答＠＠

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(sqrt2/3)^x=9/4

xlog(sqrt(2/3))=log(9/4) [x times log of square root of 2 over 3 equals to log
of 9 over 4]

x=log(9/4)/(1/2log(2/3)) [x=log of 9 over 4 divided by (1 over 2 times
log 2 over 3)]

x=(log(2/3)^-2)/(1/2log2/3)) [x equals to log, open bracket, 2 over 3, close
bracket to the power of -2]
x=-2/(1/2)
x=-4

ABSOLUTELY Wrong! i am asking how to caculate. (sqrt2/3)^x=9/4.?

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2009-11-27 19:48:02 補充：
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