ALGEBRA!!!! 4ac=c+3ab?

4ac = c + 3ab

4ac - c = 3ab

c (4a - 1) = 3ab

c = 3ab / (4a - 1)

4ac = c + 3ab
4ac - c = 3ab
c(4a - 1) = 3ab
c = 3ab/(4a - 1)

if u mean to find the value of C in term of a and b then ur answer will be

C = 3ab/(4a-1)
u can get it by taking C to left hand side and taking it common=> 4ac-c = 3ab
=> c(4a-1)=3ab
then sending the 4a-1 term to right side=> c= 3ab/(4a-1)

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c=3ab/(4a-1), a not equal 1/4

4ac - c = 3ab
c(4a-1) = 3ab
therefore,
c = 3ab / 4a-1

4ac=c+3ab
4ac-c=3ab
c(4a-1)=3ab
1. If 4a-1=0 => a=1/4
1.1 If b= 0 => Every C is a solution
1.2 If b!=0 => There is no solution
2. If 4a-1!=0 => c=3ab/(4a-1)

To make 'c' the subject of formula, you proceed as follows:

4ac-c=3ab

Since 'c' is common:
c(4a-1)=3ab

c= 3ab/(4a-1)

4ac = c + 3ab
4ac - c = 3ab
c ( 4a -1 ) =3ab
c = 3ab/ (4a-1)

You have to "solve" for 'c'. This is the proper way to phrase it.

4ac = c + 3ab

=> 4ac - c = 3ab
=> c( 4a - 1 ) = 3ab
=> c = 3ab / ( 4a - 1 )