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請指導小弟
Riccati's equation
2009-11-23 1:08 am
回答 (1)
2009-11-23 1:18 am
✔ 最佳答案
y = (1/z)(dz/dx)dy/dx = [d(1/z)/dx](dz/dx) + (1/z)(d^2z/dx^2)
dy/dx = (-1/z^2)(dz/dx)^2 + (1/z)(d^2z/dx^2)
Therefore dy/dx + y^2 + Py + Q = 0 becomes
(-1/z^2)(dz/dx)^2 + (1/z)(d^2z/dx^2) + (1/z^2)(dz/dx)^2 + (P/z)(dz/dx) + Q = 0
(1/z)(d^2z/dx^2) + (P/z)(dz/dx) + Q = 0
d^2z/dx^2 + P(dz/dx) + Qz = 0
收錄日期: 2021-04-23 23:21:02
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20091122000051KK01082