F.4 Maths (Number and Algebra)
2009-11-22 9:11 pm
Solve the following simultaneous equation.
｛log2x-log2y=2
log2(3x-2y)=1
回答 (1)
2009-11-22 9:22 pm
✔ 最佳答案
log(2)x - log(2)y = 2 ... (1)log(2)(3x-2y) = 1 ... (2)
(1) => log(2) x/y = 2
x/y = 4
x = 4y ... (3)
(2) => 3x - 2y = 2
Use (3), 3(4y) - 2y = 2
10y = 2
y = 0.2
x = 0.8
收錄日期: 2021-04-23 23:20:30
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20091122000051KK00595