Find dy/dx of the question
y = (3x2 + y2)9
thanks~
Find dy/dx of the question
2009-11-22 7:51 am
回答 (1)
2009-11-22 8:07 am
✔ 最佳答案
y = (3x^2 + y^2)^9
y' = 9(3x^2 + y^2)^8[6x + 2yy'] where y' means dy/dx
y'(3x^2 + y^2) = 9(3x^2 + y^2)^9[6x + 2yy']
y'(3x^2 + y^2) = 9y[6x + 2yy']
y'(3x^2 + y^2) = 54xy + 18y^2y'
y'(3x^2 + y^2 - 18y^2) = 54xy
y' = 54xy / (3x^2 - 17y^2)
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