z score

2009-11-22 4:32 am
the probability that a standard normal random variable, Z. falls between -2.00 and -0.44 is 0.6472, is it correct ?

回答 (1)

2009-11-22 4:48 am
✔ 最佳答案
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Pr(-2.00 < z < -0.44)
= Pr(0.44 < z < 2)
= Pr(0 < z < 2) - Pr(0 < z < 0.44)
= 0.4772 - 0.17
= 0.3072


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