點做?寫底過程唔該晒
更新1:
perry10182003 唔好意思..我想問多下x(0.02+x)=10^-13要點計? 我張x multiply 左入去.變成0.02x+x^2=10^-13下一步要點計呀..
common ion effect 急唔該幫幫手
2009-11-15 2:17 pm
ksp for AgBr is 1.0*10負13次方.how many moles of AgBr will dissove in 1.0L of 0.020mol/L KBr solution?
點做?寫底過程唔該晒
點做?寫底過程唔該晒
回答 (1)
2009-11-15 4:05 pm
✔ 最佳答案
Let x mole of AgBr will dissolve1.0L of 0.020mol/L contain KBr 0.02 mol Br-
As the Ksp of AgBr=10^-13
[Ag+][Br-]=10^-13
x(0.02+x)=10^-13
x=4.95*10^-12
4.95*10^-12 mole of AgBr will dissolve
2009-11-15 18:37:37 補充：
x(0.02+x)=10^-13
0.02x+x^2=10^-13
X^2+0.02x-10^-13=0
之後就可用quadratic equation formula去計x
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原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20091115000051KK00241