can you show work
kthankkss(:
can you solve this (x/4)-(4/x)=0?
2009-11-14 4:24 pm
回答 (7)
2009-11-14 4:56 pm
✔ 最佳答案
x/4 - 4/x = 0x/4 = 4/x
x = 4(4/x)
x^2 = 16
x = ±√16
x = ±4
2009-11-15 12:28 am
x/4 - 4/x = 0
x/4 = 4/x
cross multiply
x^2 = 16
take ^(1/2) on both side..... (square root)
x = +/- 4
x/4 = 4/x
cross multiply
x^2 = 16
take ^(1/2) on both side..... (square root)
x = +/- 4
2009-11-15 12:31 am
(x/4)-(4/x)
u multiply by 4 so its becomes
x-(16/x)
then u multiply by x so it becomes
x²-16=0
u bring 16 on the other side
x²=16
ur do the square root of 16 and x
u get x=4
so the answer is 4 :)
u multiply by 4 so its becomes
x-(16/x)
then u multiply by x so it becomes
x²-16=0
u bring 16 on the other side
x²=16
ur do the square root of 16 and x
u get x=4
so the answer is 4 :)
參考: im in high school
2009-11-15 12:29 am
(x/4)-(4/x)=0
==> [x^2 - 16] / 4x = 0
==> [x^2 - 16] = 0
==> (x-4) (x+4) = 0
==> x = 4 or x = (-4)
==> [x^2 - 16] / 4x = 0
==> [x^2 - 16] = 0
==> (x-4) (x+4) = 0
==> x = 4 or x = (-4)
2009-11-15 12:29 am
Just from looking at it I can see that it works when x = 4, but there may be another solution, so let's solve it symbolically.
x/4 = 4/x
x² = 16
x = ±4
So x = ±4, which makes sense because x=-4 produces -1+1 = 0, and x = 4 produces 1-1 = 0.
x/4 = 4/x
x² = 16
x = ±4
So x = ±4, which makes sense because x=-4 produces -1+1 = 0, and x = 4 produces 1-1 = 0.
2009-11-15 12:28 am
(x/4) - (4/x) = 0
(x/4) = (4/x)
cross-multiply
x² = 16
x = ±4
(x/4) = (4/x)
cross-multiply
x² = 16
x = ±4
收錄日期: 2021-05-01 12:52:18
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20091114082439AANHDBL