F1 代數 程式

列式解答:
(I) 2 + [(2g +1) /3] = g/5
原題是 2 + (2g+1 over 3) = g over 5。

2 + [ (2g + 1)/3 ] = g/5
(2g + 1)/3 = g/5 - 2 [兩邊一起 -2]
2g + 1 = 3g/5 - 6 [兩邊一起 X3]
2g - 3g / 5 = - 6 - 1 [把有g和沒有g的部分放在一起]
g (2 - 3/5) = -7 [把g抽出]
g (7/5) = -7
g = -5 [兩邊一起 x 7/5]

(II) [ (a+ 12)/2 ]- a = 9
(a + 12 over 2) -a =9

[(a + 12) /2] - a = 9
(a + 12) / 2 = 9 + a
a + 12 = 18 + 2a
a - 2a = 18 - 12
- a = 6
a = -6

2009-11-14 16:18:28 補充：
to: chauks07,
-a = 6不能做答案

(I) 2 + [(2g +1) /3] = g/5
10+5 [(2g +1) /3]=g
10+ (10g +5) /3=g
30+10g+5=3g
7g=-35
g=-5
(II) [ (a+ 12)/2 ]- a = 9
a+12-2a=18
-a=6