Find, in terms of n,
nC0 + 5/2 (n + 1)C1 + 5^2/3 (n + 1)C2 +....+ {[5^(n+1)]/(n + 2) } (n+1)C(n+1)
更新1:
There are some amendment. Just forgot to add the bracket. (5/2) (n + 1)C1 + [(5^2)/3] (n + 1)C2
There are some amendment. Just forgot to add the bracket. (5/2) (n + 1)C1 + [(5^2)/3] (n + 1)C2
收錄日期: 2021-04-23 23:18:53
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20091109000051KK01288