2^x=600, how do I find x?

2^x = 600
x log 2 = log 600
x × 0.3010 = 2.7782
x = 2.7782/0.3010
x = 9.23
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2^x = 600
log_2(2^x) = log_2(600)
x[log_2(2)] = log_2(8 * 75)
x = log_2(8) + log_2(75)
x = log_2(2^3) + log_2(75)
x = 3 + log_2(75)

xln2 = ln600

x = ln600 / ln2

2^x=600 take logarithms of both sides
so log (2^x)=log 600
x log 2 = log 600 so x=(log 600)/(log 2) by calculator

we get x=9.2288 approximately

x log 2 = log 600

x = log 600 / log 2

x = 9.23 ---------------( any log base may be used )