中二簡單factorization~~~

2009-11-03 7:16 am
1.6(a+1)^2+4(a+1)

2.4c^2-6dx+3cd-8cx

3.4x^3-3y+4x-3x^2y

4.36-(x-y)^2

列埋steps唔該

回答 (1)

2009-11-03 7:24 am
✔ 最佳答案
1.6(a+1)^2+4(a+1)

= (a+1)[6(a+1) + 4]

= (a+1)(6a + 10)

= 2(a+1)(3a + 5)

2.4c^2-6dx+3cd-8cx

= (4c^2 + 3cd) - (6dx + 8cx)

= c(4c + 3d) - 2x(3d + 4c)

= (c - 2x)(4c + 3d)

3.4x^3-3y+4x-3x^2y

= 4x^3 + 4x - (3y + 3x^2 y)

= 4x(x^2 + 1) - 3y(1 + x^2)

= (4x - 3y)(x^2 + 1)

4.36-(x-y)^2

= 6^2 - (x-y)^2

= (6 + x - y)(6 - (x-y) )

= (x - y + 6)(y - x + 6)





2009-11-02 23:25:30 補充:
For Q2 :

2.4c^2-6dx+3cd-8cx

= (4c^2 + 3cd) - (6dx + 8cx)

= c(4c + 3d) - 2x(3d + 4c)

= (c - 2x)(4c + 3d)

Sorry!


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