bx+ax-2x+b+a-2
X^2+4x+3
2x^2+9x-5
Factorization F.2
2009-11-03 4:47 am
回答 (5)
2009-11-05 8:51 pm
✔ 最佳答案
a(x+1)+b(x+1)-2(x+1)=(a+b-2)(x+1)
(x+1)(x+3)
(2x-1)(x+5)
2009-11-04 3:22 am
1. bx+ax-2x+b+a-2
=x(b+a-2) +(b+a-2)
=(x-1)(a+b-2)//
2. x^2+4x+3
= (x^2+3x)+x+3
=x(x+3)+(x+3)
=(x+1)(x+3)//
2009-11-03 19:23:16 補充：
3)
2x^2 + 9x - 5
(2x - 1)(x + 5)
2009-11-03 19:43:46 補充：
3. 2x^2 + 9x - 5
=2x^2 +10x-(x+5)
=2x(x+5)-(x+5)
=(2x-1)(x+5)//
=x(b+a-2) +(b+a-2)
=(x-1)(a+b-2)//
2. x^2+4x+3
= (x^2+3x)+x+3
=x(x+3)+(x+3)
=(x+1)(x+3)//
2009-11-03 19:23:16 補充：
3)
2x^2 + 9x - 5
(2x - 1)(x + 5)
2009-11-03 19:43:46 補充：
3. 2x^2 + 9x - 5
=2x^2 +10x-(x+5)
=2x(x+5)-(x+5)
=(2x-1)(x+5)//
參考: , me
2009-11-03 6:10 am
1)
bx + ax - 2x + b + a - 2
(x + 1)b + (x + 1)a - (2x + 2)
(x + 1)(a + b) - 2(x + 1)
(x + 1)(a + b - 2)
2)
x^2 + 4x + 3
(x + 3)(x + 1)
3)
2x^2 + 9x - 5
(2x - 1)(x + 5)
You can use calculator in no.2,3
bx + ax - 2x + b + a - 2
(x + 1)b + (x + 1)a - (2x + 2)
(x + 1)(a + b) - 2(x + 1)
(x + 1)(a + b - 2)
2)
x^2 + 4x + 3
(x + 3)(x + 1)
3)
2x^2 + 9x - 5
(2x - 1)(x + 5)
You can use calculator in no.2,3
2009-11-03 5:01 am
(b+a-2)(x+1)
(x+3)(x+1)
(x+5)(2x-1)
(x+3)(x+1)
(x+5)(2x-1)
2009-11-03 4:54 am
1) bx+ax-2x+b+a-2
=bx+b+ax+a-2x-2
=b(x+1)+a(x+1)-2(x+1)
=(b+a-2)(x+1)
之後你慢慢研究la
搵個Factor再乘
記住要同terms
再combine
先至Factorize
再group埋
=bx+b+ax+a-2x-2
=b(x+1)+a(x+1)-2(x+1)
=(b+a-2)(x+1)
之後你慢慢研究la
搵個Factor再乘
記住要同terms
再combine
先至Factorize
再group埋
收錄日期: 2021-04-15 21:48:27
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20091102000051KK01412