Factorize the follow expression
x^(2) + 6x + 8 - x(x^(2) - 4x - 12)
Help me please!!! 20 points
f2 factorization question x 1
2009-10-31 3:00 am
回答 (5)
2009-10-31 6:34 am
✔ 最佳答案
x^(2) + 6x + 8 - x(x^(2) - 4x - 12)=x^(2) + 2x +4x + 8 - x(x^(2) - 6x +2x- 12)
=x(x+2)+4(x+8)-x[x(x-6)+2(x-6)]
=(x+2)(x+4)-x(x-6)(x+2)
=(x+2)[(x+4)-x(x-6)]
=(x-2)(x+4-x^(2)+6x)
=(x+2)( -x^(2)+7x+4)
This is the answer
參考: me
2009-10-31 7:03 am
cross method
2009-10-31 3:17 am
x^(2) + 6x + 8 - x(x^(2) - 4x - 12)
=(X+4)(X+2)-X(X+2)(X-6)
=(X+2)[(X+4)-X(X-6)]
=(X+2)(X+4-X^2+6X)
=(X+2)(-X^2+7X+4)
.......無錯的話,這就是ANS.
=(X+4)(X+2)-X(X+2)(X-6)
=(X+2)[(X+4)-X(X-6)]
=(X+2)(X+4-X^2+6X)
=(X+2)(-X^2+7X+4)
.......無錯的話,這就是ANS.
參考: 我
2009-10-31 3:08 am
x^2 + 6x + 8 - x(x^2 - 4x - 12)
= (x + 4)(x + 2) - x(x - 6)(x + 2)
= (x + 2)[x + 4 - x(x - 6)]
= (x + 2)[x + 4 - x^2 + 6x]
= -(x + 2)(x^2 - 7x - 4)
= (x + 4)(x + 2) - x(x - 6)(x + 2)
= (x + 2)[x + 4 - x(x - 6)]
= (x + 2)[x + 4 - x^2 + 6x]
= -(x + 2)(x^2 - 7x - 4)
2009-10-31 3:07 am
x^2+6x+8-x(x^2-4x-12)
=(x+2)(x+4)-x(x+2)(x-6)
=(x+2)(x+4-x(x-6))
=(x+2)(x+4-x^2+6x)
=(x+2)(-x^2+7x+4)
=(x+2)(x+4)-x(x+2)(x-6)
=(x+2)(x+4-x(x-6))
=(x+2)(x+4-x^2+6x)
=(x+2)(-x^2+7x+4)
收錄日期: 2021-04-15 22:04:16
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