maths~~~~~~

x = √(6+(√(6+(√(6+(√(6+...

x^2 = 6+(√(6+(√(6+(√(6+...

x^2 = 6 + x






2009-10-29 20:45:47 補充：
x^2 - x - 6 = 0

(x + 2)(x - 3) = 0

x = 3 or - 2 (rejected since √k is not negative)

2009-10-30 16:40:33 補充：
Checking :

√(6+(√(6+(√(6+(√(6+... = 3

6+(√(6+(√(6+(√(6+... = 3^2 = 9

√(6+(√(6+(√(6+... = 9-6 = 3

Since 3 is a root of x^2 = 6 + x,

so √(6+(√(6+(√(6+(√(6+... = 3 is a root of x^2 = 6 + x.