✔ 最佳答案
家用的電器裝置都是並聯.
2009-10-31 22:07:34 補充:
We Can Demostrate By Calculations.
In 100W,220V,
After Calculated,We've Got 0.45A,489 Ohms.
In 50W,220V,
After Calculated,We've Got 0.22A,1000 Ohms.
If One 100W Connected In 220V,
Since The Resistance Is 489 Ohms,So The Current Is 0.45A.
If One 50W Connected In 220V,
Since The Resistance Is 1000Ohms,So The Current Is 0.22A.
If Two 50W Connected In SERIES In 220V,
Since The Resistance Is 1000+1000 Ohms Altogether,So The Current Is 0.11A,
If Two 50W Connected In PARRLLEL In 220V,
Since The Resistance Is 500 Ohms Altogether After Calculation,So The Current Is 0.44A.
By After Calculation,
We've Got
0.45A for one 100W,
0.22A for one 50W,
0.11A for two 50W in series,
0.44A for two 50W in parallel.
In Conclusion,
Two 50W Light Bulb Connect In Series Is Blighter Than 100W.
2009-11-02 00:15:32 補充:
oh...sorry..thx you remind me,
my calculation is correct,but th conclusion is wrong xp"
100W Bulb is the most brighttest,its brighter than 50W parallel 0.01A(10mA),
its almost have identical brightness.