Statistics 1
2009-10-28 7:58 pm
回答 (1)
2009-10-28 8:40 pm
✔ 最佳答案
(a) point estimate=618/8500=0.0727. A 95% C.I. is(0..0727-1.96*√[(0.0727)(0.9273)/8500]<p<(0..0727-1.96*√[(0.0727)(0.9273)/8500])
(0.0699<p<0.0755)
(b) Let the required number is n. Then
1.96*√(0.25/n)=0.2%
n>=240100
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