How do i solve an inequality like this 4x-5>7-8x?
回答 (6)
2009-10-25 5:14 pm
✔ 最佳答案
Same as an equality: Treat both sides the same. The only difference is when you multiply or divide both sides by a negative number, the direction of the > changes to <. But, that doesn't occur here.Add 8x to both sides
4x - 5 > 7 - 8x
12x - 5 > 7
Add 5 to both sides
12x > 12
Divide both sides by 12
x > 1
2009-10-26 12:20 am
4x - 5 > 7 - 8x
4x + 8x > 7 + 5
12x > 12
x > 1
Answer: x > 1
4x + 8x > 7 + 5
12x > 12
x > 1
Answer: x > 1
2009-10-26 12:44 am
4x - 5 > 7 - 8x
4x + 8x > 7 + 5
12x > 12
x > 12/12
x > 1
4x + 8x > 7 + 5
12x > 12
x > 12/12
x > 1
2009-10-26 12:22 am
12 x > 12
x > 1
x > 1
2009-10-26 12:14 am
4x-5>7-8x
4x + 8x>7 +5
12 x > 12
x > 1
QED
4x + 8x>7 +5
12 x > 12
x > 1
QED
2009-10-26 12:13 am
You put the x variables on one side, and the numbers on the other side, and solve as if it's a normal equation... but instead of =, you have >.
4x+8x>7+5
12x>12
by dividing both sides by 12, to have the coefficient of x to be one,
x>1
4x+8x>7+5
12x>12
by dividing both sides by 12, to have the coefficient of x to be one,
x>1
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