How do I factor 2x(-4-2x^2)?
回答 (5)
2009-10-25 4:10 pm
✔ 最佳答案
1)2x(-4 - 2x^2)
= 2x(-2)(2 + x^2)
= -4x(2 + x^2)
2)
x^3/(x^2 - 12)
|x^2 - 12| > 0
x^2 - 12 > 0 , x^2 - 12 < 0
x^2 - 12 > 0
x^2 > 12
x < ±√12
x < ±√(2^2 * 3)
x < ±2√3
x^2 - 12 < 0
x^2 < 12
x < ±√12
x < ±2√3
Domain: x < ±2√3, x > ±2√3
2009-10-25 11:44 pm
–4x(x + iâ2)(x – iâ2)
2009-10-25 11:02 pm
x=0 is a factor {bcoz by substituting x=0, the whole value becomes 0}
The other possibility to make the total value zero is
-4-2x^2 is equal to 0
-4-2x^2=0
2x^2=4
x=+ or - sqrt2
The 3 domains are 0 , plus sqrt(2) and minus sqrt(2)
The other possibility to make the total value zero is
-4-2x^2 is equal to 0
-4-2x^2=0
2x^2=4
x=+ or - sqrt2
The 3 domains are 0 , plus sqrt(2) and minus sqrt(2)
參考: my own intelligence
2009-10-25 11:00 pm
2x(–4–2x²2)
it is mostly factored already, you can pull a –2 out also
–4x(x² + 2)
the x² +2 can be factored, but only with imaginary numbers
i = â(-1)
–4x(x + iâ2)(x – iâ2)
.
it is mostly factored already, you can pull a –2 out also
–4x(x² + 2)
the x² +2 can be factored, but only with imaginary numbers
i = â(-1)
–4x(x + iâ2)(x – iâ2)
.
2009-10-25 11:00 pm
common factor
denominator cannot be zero. Solve x^2 - 12 = 0 and exclude solutions from the domain of the relation.
denominator cannot be zero. Solve x^2 - 12 = 0 and exclude solutions from the domain of the relation.
參考: retired math teacher
收錄日期: 2021-05-01 12:53:06
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