solve the equation: 1/3(27x + 18) = 12 + 6(x - 4)?

Here's how I solved the equation. If you need more equations to be simplified then go to http://www.algebra.com/services/rendering/simplifier.mpl
Answer below:-

So, 1/3(27x + 18) = 12 + 6(x - 4)

or, 9x + 6 = 12 + 6x - 24

or, 9x - 6x = 12 - 24 - 6

or, 3x = -18

or, x = -18/3

Therefore, x = -6

_Hope it helped_ [-_-]

Let's simplify one side at a time

1/3(27x + 18) = 12 + 6(x - 4)

27x/3 - 18/3 = 12 + 6(x-4)

9x - 6 = 12 + 6(x-4)

9x - 6 = 12 + 6x - 24

3x - 6 = 12 - 24

3x - 6 = -12

3x = -6

x = -2

x=-6

1/3(27x + 18) = 12 + 6(x - 4)
(27x + 18)/3 = 12 + 6(x) - 6(4)
27x/3 + 18/3 = 12 + 6x - 24
9x + 6 = 6x + 12 - 24
9x + 6 = 6x - 12
9x - 6x = -6 - 12
3x = -18
x = -18/3
x = -6

1/3(27x + 18) = 12 + 6(x - 4)
9x + 6 = 12 + 6x - 24
3x + 6 = 12 - 24
3x = -18
x = -6

1/3(27x+18) = 12+6(x-4)
9x+6 = 12+6x-24
-6x -6x
3x+6=12-24
-6 -12
-6
3x=-18
x=-6

1/3(27x+18)=12+6x-24
1/3(27x+18)=(6x-12)
27x+18=3(6x-12)
27x+18=18x-36
27x-18x=-36-18
9x=-54
x=-54/9
x=-6

1/3(27x + 18) = 12 + 6(x - 4)

=> 9x + 6 = 6x - 24 +12

=> 3x = -18 or x = - 6