maths f.3 expand question

(1-m)^5 = (-m + 1)^5

sub x = m to (*) :

(-m+1)^5 = (-m)^5 + 5(-m)^4 + 10(-m)^3 + 5(-m)^2 + 5(-m) + 1

= -m^5 + 5m^4 - 10m^3 + 5m^2 - 5m + 1



2009-10-24 11:36:13 補充：
Correction:
sub x = - m to (*) :

2009-10-24 11:40:03 補充：
Your question is error !!!

(x+1)^5 = x^5+5x^4+10x^3+10x^2+5x+1............(*)

(1-m)^5 = (-m + 1)^5

sub x = - m to (*) :

(-m+1)^5 = (-m)^5 + 5(-m)^4 + 10(-m)^3 + 10(-m)^2 + 5(-m) + 1

= -m^5 + 5m^4 - 10m^3 + 10m^2 - 5m + 1