A.maths absolute value

3a) Solve | 3 - x | = 3x + 2
If 3 >= x,
3 - x = 3x + 2
1 = 4x
x = 1/4
If 3 < x,
x - 3 = 3x + 2
-5 = 2x
x = -5/2 (rejected)
3b) Hence, solve | 3 - |2-x| | = | 3x - 6 | + 2
| 3 - |2-x| | = | 3x - 6 | +2
| 3 - |2-x| | = 3 |2-x| + 2 since |x-2| = |2-x|
Let u = |2-x|
| 3 - u | = 3u + 2
From (a), u = |2-x| = 1/4
2-x = 1/4 or x-2 = 1/4
x = 7/4 or x = 9/4