3y-2x-1=0
3x+4y+10=0
use the method of substitution to solve the simultaneous equations
中二簡單simultaneous equations~~
2009-10-21 7:33 am
回答 (2)
2009-10-21 7:54 am
✔ 最佳答案
3y - 2x - 1 = 0 ... (1)3x + 4y + 10 = 0 ... (2)
(1) => 3y = 2x + 1
y = (2x + 1)/3 ... (3)
Sub into (2), 3x + 4(2x + 1)/3 + 10 = 0
9x + 4(2x + 1) + 30 = 0
9x + 8x + 4 + 30 = 0
17x = -34
x = -2
Sub into (3), y = (-4 + 1)/3 = -1
2009-10-25 7:55 am
3y - 2x - 1 = 0 ... (1)
3x + 4y + 10 = 0 ... (2)
from1 we get 3y = 2x + 1
y = (2x + 1)/3 ... (3)
Sub into (2)
3x + 4(2x + 1)/3 + 10
= 0
9x + 4(2x + 1) + 30
= 0
9x + 8x + 4 + 30
= 0
17x = -34
x = -2
Sub into (3)
, y = (-4 + 1)/3
= -1
so x=-2 y=-1
如果你仲有唔明..可以問我//[email protected]
3x + 4y + 10 = 0 ... (2)
from1 we get 3y = 2x + 1
y = (2x + 1)/3 ... (3)
Sub into (2)
3x + 4(2x + 1)/3 + 10
= 0
9x + 4(2x + 1) + 30
= 0
9x + 8x + 4 + 30
= 0
17x = -34
x = -2
Sub into (3)
, y = (-4 + 1)/3
= -1
so x=-2 y=-1
如果你仲有唔明..可以問我//[email protected]
收錄日期: 2021-04-23 23:22:15
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20091020000051KK01747