28y=3[16-4(1-y)]
7[2(x-3)+x]=4[1-3(x+1)]
[5(3-x)]/8-(x+3)/2=0
(t+1)/3-(a+4)/4=a+1
唔該幫我計計d maths(中一)
2009-10-21 1:22 am
回答 (1)
2009-10-21 1:35 am
✔ 最佳答案
28y=3[16-4(1-y)]28y/3=16-4+4y
(28y/3)-4y=12
y=2.25
7[2(x-3)+x]=4[1-3(x+1)]
7[3x-6]=4[-2-3x]
21x-42=-8-12x
33x=34
x=34/33
[5(3-x)]/8-(x+3)/2=0
[15-5x]=4x+12
9x=3
x=1/3
(t+1)/3-(a+4)/4=a+1
4t+4-3a-12=12a+12
4t=15a+20
t=5(3a+4)/4
收錄日期: 2021-04-23 19:26:47
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20091020000051KK00787