Quadratic Equation:
Given α and β are the roots of 2x^2 +6x+3=0.
Find α^3 - β^3
α^3 - β^3
2009-10-19 1:48 am
回答 (3)
2009-10-19 3:06 am
✔ 最佳答案
As follows:圖片參考：http://i.imagehost.org/0970/ScreenHunter_01_Oct_18_19_03.gif
2009-11-07 17:34:15 補充：
http://a.imagehost.org/0419/ScreenHunter_02_Nov_07_17_31.gif
2009-10-21 2:36 am
2009-10-19 1:59 am
α^3 - β^3
=α^3+αβ^2+α^2β-αβ^2-α^2β-β^3
=(α- β)(α^2 +αβ+ β^2)
=α^3+αβ^2+α^2β-αβ^2-α^2β-β^3
=(α- β)(α^2 +αβ+ β^2)
收錄日期: 2021-04-23 20:38:19
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20091018000051KK01373