1. m^2(1-n)^2-m^2n^2
2a. 4x^2-17xy-15y^2
b. 將a部得出的答案代入並計算: 4x^2-17xy-15y^2+24x+18y
3. 8x^3+512y^6
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中三數學問題 (多項式)
2009-10-18 11:05 pm
回答 (2)
2009-10-18 11:57 pm
✔ 最佳答案
1. m^2(1-n)^2-m^2n^2 =-m^2[(1-n)^2 - n^2]
= m^2[(1-n+n)(1-n-n)]
= m^2(1-2n)
2a. 4x^2-17xy-15y^2
= (4x+3y)(x-5y)
2b. 4x^2-17xy-15y^2+24x+18y
= (4x+3y)(x-5y) +6(4x+3y)
=(4x+3y)(x-5y+6)
3. 8x^3+512y^6
= (2x)^3 +(8y^2)^3
= (2x+8y^2)[ (2x)^2 -(2x)(8y^2) +(8y^2)^2]
= (2x+8y^2)( 4x^2 -16xy^2 +64y^4)
= 2(x+4y^2)(4)(x^2-4xy^2+16y^4) 可以不用寫這個step
=8(x+4y^2)(x^2-4xy^2+16y^4)
2009-10-19 12:04 am
2. a
4x2 - 17xy-15y2=(4x+3y)(x-5y)
b) therefore=(4x+3y)(x-5y)+24x+18y=(4x+3y)(x-5y)+(4x+3y)(6)
=(4x+3y)(x-5y+6)
3.qs
=8(x 3+64y6 )=8(x+4y)(x2-4xy+16y2)
1.qs=m^2[ (1-n)^2-n^2 ]
=m^2(1-2n)
4x2 - 17xy-15y2=(4x+3y)(x-5y)
b) therefore=(4x+3y)(x-5y)+24x+18y=(4x+3y)(x-5y)+(4x+3y)(6)
=(4x+3y)(x-5y+6)
3.qs
=8(x 3+64y6 )=8(x+4y)(x2-4xy+16y2)
1.qs=m^2[ (1-n)^2-n^2 ]
=m^2(1-2n)
收錄日期: 2021-04-13 16:53:42
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