擲2枚骰子，求擲得第1枚或第2枚骰的結果是6點，的概率。
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概率 F.5 Maths
2009-10-17 9:43 pm
回答 (4)
2009-10-17 9:57 pm
✔ 最佳答案
擲得第1枚及第2枚骰的結果都不是6點的概率 = (5/6)(5/6) = 25/36擲得第1枚或第2枚骰的結果是6點的概率 = 1 - 25/36 = 11/36
2009-10-18 12:55 am
P(both 1st and 2nd dice is 6) = (1/6)(1/6) = 1/36.
P(both 1st and 2nd dice are not 6) = (1 - 1/6)(1 - 1/6) = (5/6)(5/6) = 25/36.
So P(either 1st or 2nd dice is 6) = 1 - 1/36 - 25/36 = 10/36 = 5/18.
P(both 1st and 2nd dice are not 6) = (1 - 1/6)(1 - 1/6) = (5/6)(5/6) = 25/36.
So P(either 1st or 2nd dice is 6) = 1 - 1/36 - 25/36 = 10/36 = 5/18.
2009-10-17 10:47 pm
概率:1-25/36=11/36
2009-10-17 10:17 pm
1/6+1/6
1/3
1/3
收錄日期: 2021-04-19 15:59:10
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https://hk.answers.yahoo.com/question/index?qid=20091017000051KK00722