Solve 3m = 2 – m ???

A

element the numerator and denominator one after the other: 3m^2 - 27n^2 => 3 * (m^2 - 9n^2) => 3 * (m - 3n) * (m + 3n) 3m + 9n => 3 * (m + 3n) we've: (3 * (m - 3n) * (m + 3n)) / (3 * (m + 3n)) go out common factors and additionally you're left with: (m - 3n) / a million => m - 3n There you go. by capacity of ways, the adaptation of two squares: a^2 - b^2, continuously factors to (a - b) * (a + b), in case you have been thinking how I factored m^2 - 9n^2

4 m = 2

m = 1/2

OPTION A

3m = 2 - m
3m + m = 2
4m = 2
m = 2/4
m = 1/2 (0.5)
(answer A)

3m = 2 - m
therefore 3m + m = 2
therefore 4m = 2
therefore m = 2/4
therefore m =1/2

hence answer is (A)

A. 3(1/2)=2-(1/2) 1.5=1.5 true
B. 3(2)= 2-2 6=0 false
C. 3(1)= 2-1 3=1 false
D. 3(-1/2)=2-(-1/2) -1.5=2.5 false

I think this was what you were asking. Hope this helps!

Add -M to both sides which makes it 4m=2
Then Divide by four from both sides and m=1/2
Bubble in A. 1/2
Voila

A

3m=2-m
4m=2
2/4=m
m=1/2

3m= 2 - m
+m +m

4m=2
/4 /4

m= 1/2

:)

3m + m = 2
4m = 2
/ 4
m= 2/4
A!

A. 1/2