*Simplify.* √27 - √8 + 2√2?

2009-10-15 3:18 pm
a. 3√3 - 2√2
b. Ø
c. 3√3 - 4√2
d. 3√3

回答 (12)

2009-10-15 3:34 pm
✔ 最佳答案
√27 - √8 + 2√2
=√(9*3)-√(4*2)+2√2
=3√3-2√2+2√2
=3√3 answer//

Answer is d.3√3
2009-10-16 12:02 am
3√3.
2009-10-15 10:35 pm
answer is D=3√3
2009-10-15 10:30 pm
We know that √3 and √2 cannot be added or subtracted together. Think of these as x and y. You cannot join x and y together somehow with addition or subtraction to get one term like xy or something, so we have to keep the √3 and the √2 terms separate.

For √27, this can be written as √(3*3*3) = √(3^2)*√3 = 3√3. Since 3^2=9 is a perfect square, and 9 is a factor of 27, we can take the square root of this and leave the 3 still under the radical.

Same goes for √8. This can be written as √(2*2*2) = √(2^2)*2 = 2√2. 2^2=4 is also a perfect square. These (that is, 1, 4, 9, 16, 25, etc are the only factors that can be simplified under a radical).

Now think of √2 as a variable, x. We have the form -2x + 2x = 0. We can add however many of √2 terms together so long as the all have the common factor of √2. Then we have 3√3 - 2√2 + 2√2 = 3√3.

Have fun!
2009-10-15 10:28 pm
√27 - √8 + 2√2
= √(3^2 * 3) - √(2^2 * 2) + 2√2
= 3√3 - 2√2 + 2√2
== 3√3
(answer d)
2009-10-15 10:26 pm
√27 - √8 + 2√2 = √(3*3*3) - √(2*2*2) + 2√2
. . . . . . . . . . . .= 3√3 - 2√2 + 2√2
. . . . . . . . . . . .= 3√3 . . (option d)
2009-10-15 10:25 pm
√27 - √8 + 2√2


√27 - 2√2 + 2√2


√27

√9*3

3√3===>(d)
2009-10-15 10:23 pm
√27 - √8 + 2√2 = 3√3 - 2√2 + 2√2 = 3√3

a. 3√3 - 2√2
b. Ø
c. 3√3 - 4√2
d. 3√3 ................... correct answer
2009-10-15 10:23 pm
√27-√8+2√2
=√9√3-√4√2+2√2
=3√3-2√2+2√2
=3√3.

So, the answer is d.

:-)
2009-10-15 10:23 pm
√27= √9*3 = √9*√3
√9 =3
so ,√27 = 3√3
√8 = √4*2 =√4√2 =2√2

√27 - √8 + 2√2 = 3√3 - 2√2+2√2 = 3√2
So answer is 3√3


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