中一math(明天要交)(20點)

2p-4(p-1)-1=8p+25
2p-4p-4-1=8p+25
2p-4p-8p=25+4+1
-10p=30
p= -3


p.s未必對

2[p-2(p-1)]-1=8p+25
2[p-2p+2]-1=8p+25
2p-4p+4=8p+25
-10p=21
p=-2.1

2009-10-17 10:46:46 補充：
2[p-2(p-1)]-1=8p+25
2[p-2p+2]-1=8p+25
2p-4p+4=8p+25
-10p=21
p=-2.1

2009-10-18 11:52:25 補充：
2[p-2(p-1)]-1=8p+25
2[p-2p+2]-1=8p+25
2p-4p+4-1=8p+25
-10p=28
p=-2.8

2009-10-18 11:52:47 補充：
2[p-2(p-1)]-1=8p+25
2[p-2p+2]-1=8p+25
2p-4p+4-1=8p+25
-10p=28
p=-2.8

2009-10-18 11:54:23 補充：
2[p-2(p-1)]-1=8p+25
2[p-2p+2]-1=8p+25
2p-4p+4-1=8p+25
-10p=28
p=-2.8

2[p-2(p-1)]-1=8p+25



2[p-2p+2]-1=8p+25 <<< -2*p =-2p , -2*-1=+2 therefore: -2p+2



2p-4p+4-1=8p+25 <<< 2*p - 2*2p + 2*2



-10p=22 <<< 2p-4p-8p = 25-4+1



p=-2.2 <<< 22/-10

2[p-2(p-1)]-1=8p+25
2[p(p-1)-2(p-1)]-1+1=8p+25+1
2(p^2-p-2p+2)=8p+26
2(p^2-3p+2)=8p+26
2p^2-6p+4=8p+26
2p^2-6p+4-4=8p+26-4
2p^2-2p=22
2p(p-1)=22
p(p-1)=11
p-1=11/p
p=1+11/p
p^2=12
p=2根3

2[p-2(p-1)]-1=8p+25
2[p-(2p-2)]-1=8p+25
2[-p+2]-1=8p+25
-2p+3=8p+25
10p=-22
p=-2.2

2[p-2(p-1)]-1=8p+25

2(p-2p+2)-1=8p+25

2(-p+2)-1=8p+25

-2p+4-1=8p+25

-2p-8p=25-4+1

-10p=22

p=-22/10

=- 0.22

2009-10-15 20:08:47 補充：
sorry, p should be -2.2

hjgjhbvvgcvc

2[p-2(p-1)]-1=8p+25
2[p-2p-2]-1=8p+25
2[p-2p]-1=8p+25
2p-4p-1=8p+25
2p-4p-8p=25+1
-10p=26
-p=10/26
p=-10/26