Trigonometry (2) help~ quick

2009-10-16 3:27 am
1. tanθ/sinθ -sin^2θ/cosθ

回答 (2)

2009-10-16 3:36 am
✔ 最佳答案
(tan @ / sin @) - (sin^2 @ / cos @)

= [(sin@ / cos@) / sin@] - (sin^2 @ / cos@)

= (1 / cos@) - (sin^2@ / cos@)

= (1 - sin^2@) / cos@

= cos^2@ / cos@

=cos@
2009-10-21 3:41 am


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