if f(x)=x^2+6x, find f(x+3)?
回答 (6)
2009-10-14 2:46 pm
✔ 最佳答案
f(x+3)=(x+3)^2+6(x+3)=x^2+6x+9+6x+18
=x^2+12x+27 answer//
2009-10-14 2:40 pm
f(x ) = x^2 + 6x
f(x+3)
= (x+3)^2 + 6(x+3)
= x^2 + 6x + 9 + 6x + 18
= x^2 + 12x + 27
f(x+3)
= (x+3)^2 + 6(x+3)
= x^2 + 6x + 9 + 6x + 18
= x^2 + 12x + 27
2009-10-14 2:52 pm
f(x) = x^2 + 6x
f(x + 3) = (x + 3)^2 + 6(x + 3)
f(x + 3) = (x + 3)[(x + 3) + 6)]
f(x + 3) = (x + 3)(x + 3 + 6)
f(x + 3) = (x + 3)(x + 9)
f(x + 3) = (x + 3)^2 + 6(x + 3)
f(x + 3) = (x + 3)[(x + 3) + 6)]
f(x + 3) = (x + 3)(x + 3 + 6)
f(x + 3) = (x + 3)(x + 9)
2009-10-14 2:45 pm
Just plug in (x + 3) into every x you see in the function.
From f(x) --> f(x + 3):
f(x + 3) = (x + 3) ^ 2 + 6(x + 3)
Simplifying,
f(x + 3) = x ^ 2 + 6x + 9 + 6x + 18
or
f(x + 3) = x ^ 2 + 12x + 27
From f(x) --> f(x + 3):
f(x + 3) = (x + 3) ^ 2 + 6(x + 3)
Simplifying,
f(x + 3) = x ^ 2 + 6x + 9 + 6x + 18
or
f(x + 3) = x ^ 2 + 12x + 27
2009-10-14 2:41 pm
f(5) would be found by substituting x = 5 into x^2 + 6x.
In the same way, f(x + 3) is found by substituting (x + 3) for x:
f(x + 3) = (x + 3)^2 + 6(x + 3)
= x^2 + 6x + 9 + 6x + 18
= x^2 + 12x + 27
In the same way, f(x + 3) is found by substituting (x + 3) for x:
f(x + 3) = (x + 3)^2 + 6(x + 3)
= x^2 + 6x + 9 + 6x + 18
= x^2 + 12x + 27
2009-10-14 2:41 pm
f(x + 3) = (x + 3)^2 + 6(x + 3)
It's not too hard. ;-)
It's not too hard. ;-)
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