1.x^12-16
2.x^6-2x^3y^3+y^6
中三因式分解
2009-10-14 5:29 am
回答 (2)
2009-10-14 5:38 am
✔ 最佳答案
1.x^12-16
= (x^6)^2 - 4^2
= (x^6 - 4)(x^6 + 4)
= [(x^3)^2 - 2^2](x^6 + 4)
= (x^3 - 2)(x^3 + 2)(x^6 + 4)
2.x^6-2x^3y^3+y^6
= (x^3)^2 - 2(x^3)(y^3) + (y^3)^2
= (x^3 - y^3)^2
= [(x - y)(x^2 + xy + y^2)]^2
2009-10-14 5:43 am
1.x^12-16
=(x^6-4)(x^6+4)
=(x^3-2)(x^3+2)(x^6+4)
2.x^6-2x^3y^3+y^6
=(x^3-y^3)
=(x-y)(x^2+xy+y^2)
=(x^6-4)(x^6+4)
=(x^3-2)(x^3+2)(x^6+4)
2.x^6-2x^3y^3+y^6
=(x^3-y^3)
=(x-y)(x^2+xy+y^2)
收錄日期: 2021-04-21 22:04:13
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20091013000051KK01554