Evaluate 2y²(x +y) when x=8 and y=3?

2y^2(x + y) (x = 8,y = 3)

Substitute 8 and 3 for x and y respectively.
2(3^2)(8 + 3)
= 2(9)(11)
= 18(11)
= 198

198

18 ( 8 + 3 ) = 144 + 54 = 198

You plug in 8 and 3 in place of x and y, respectively.

= 2y²(x + y)
= 2(3)²(8 + 3)
= 2(9)(8 + 3)
= 18(11)
= 198 (Answer)

Hope this helps!

198

2(3)^2(8+3)=
2(9)(8+3)=
2(9)11=
2(99)=
198

This translwates into:

2x3x3x(11)=198