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更新1:
仲有一題... 我試過做 不過答案又唔知岩唔岩.... 12a^2c^2-4ac^2 唔該....
更新2:
唔該曬~~ 我唸我應該明白了~ 唔該~~
因式分解Form2唔識做help~~
回答 (4)
2009-10-13 4:55 am
✔ 最佳答案
4(x-2)-(x-2)(x+1)= (x-2)[4 - (x+1)]
= (x-2)(4 - x - 1)
= (x - 2)(3 - x)
2009-10-12 21:09:25 補充：
12a^2c^2-4ac^2
= 4ac^2 (3a) - 4ac^2
= 4ac^2 (3a - 1)
002 waiyanandrea :
題目是因式分解
你做乜展開?
2009-10-13 7:33 am
4(x-2)-(x-2)(x+1)
= 4x-8x-(x^2+x-2x-2)
= -4x-(x^2-x-2)
= -4x-x^2+x+2
= x^2-3x+2
= 4x-8x-(x^2+x-2x-2)
= -4x-(x^2-x-2)
= -4x-x^2+x+2
= x^2-3x+2
2009-10-13 5:09 am
001 沒錯
題目是因式分解
不是擴展
題目是因式分解
不是擴展
2009-10-13 5:02 am
4(x-2)-(x-2)(x+1)
= 4x-8x-(x^2+x-2x-2)
= -4x-(x^2-x-2)
= -4x-x^2+x+2
= x^2-3x+2
2009-10-12 21:04:06 補充：
001好似睇錯sign -3-
= 4x-8x-(x^2+x-2x-2)
= -4x-(x^2-x-2)
= -4x-x^2+x+2
= x^2-3x+2
2009-10-12 21:04:06 補充：
001好似睇錯sign -3-
參考: me=]
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