1.(2x-3)^2+10x-15
ans:2(2x-3)(x+1)
2.(x+2)62-(x+2)(y-3)-6(y-3)^2
ans:(x-3y+11)(x+2y-4)
3.3(x+7)^2+(x+7)(x-6)-14(x-6)-14(x-6)^2
ans:(10x-21)(19-x)
F.3 factorization(20)today!!
2009-10-13 3:55 am
回答 (1)
2009-10-13 4:27 am
✔ 最佳答案
1.(2x-3)2+10x-15 =(2x-3)2+5(2x-3)
=(2x-3)[(2x-3)+5]
=(2x-3)(2x+2)
=2(2x-3)(x+1)
2.(x+2)2-(x+2)(y-3)-6(y-3)2
=[(x+2)-3(y-3)][(x+2)+2(y-3)]
=(x-3y+11)(x+2y-4)
3.3(x+7) 2+(x+7)(x-6)-14(x-6)-14(x-6)2
=[3(x+7)+7(x-6)] [(x+7)-2(x-6)]-14(x-6)
=(10x-21)(-x+19)
=(10x-21)(19-x)
收錄日期: 2021-04-23 20:44:11
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20091012000051KK01245