A solenoid of length 0.250 m and radius 0.0200 m is comprised of 120 turns of wire. Determine the magnitude of the magnetic field at the center of the solenoid when it carries a current of 15.0 A.
please show your solution steps by steps, thanks!!!!!
answers choose from:
zero tesla
4.52 × 10–3 T
9.05 × 10–3 T
7.50 × 10–3 T
calculation of magnetic field
2009-10-09 4:09 am
回答 (2)
2009-10-09 4:16 am
✔ 最佳答案
The magnetic field of a solenoid at its centre is given byB = u0NI / L
where u0 is permeability of vacuum, u0 = 4pi X 10-7
N is number of turns of the solenoid
I is current
L is the length of the solenoid
So, B = (4pi X 10-7)(120)(15.0) / 0.25
= 9.05 X 10-3 T
參考: Physics king
2009-10-13 4:23 am
The magnetic field of a solenoid at its centre is given by
B = u0NI / L
where u0 is permeability of vacuum, u0 = 4pi X 10-7
N is number of turns of the solenoid
I is current
L is the length of the solenoid
So, B = (4pi X 10-7)(120)(15.0) / 0.25
= 9.05 X 10-3 T
B = u0NI / L
where u0 is permeability of vacuum, u0 = 4pi X 10-7
N is number of turns of the solenoid
I is current
L is the length of the solenoid
So, B = (4pi X 10-7)(120)(15.0) / 0.25
= 9.05 X 10-3 T
收錄日期: 2021-04-19 15:28:05
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