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打錯字 應該是solve
First order differential.
2009-10-04 9:48 pm
回答 (1)
2009-10-04 10:15 pm
✔ 最佳答案
dy/dx = xexp(y - x2)dy/dx = xexp(y)/exp(x2)
By separating variables,
S e-y dy = S xe(-x^2) dx
-e-y = -1/2 S e(-x^2) d(-x2)
e-y = 1/2 e(-x^2) + C
When x = 0, y = 0
So, C = 1 - 1/2 = 1/2
Therefore, e-y = (e-x^2 + 1)/2
ey = 2/(e-x^2 + 1)
y = ln[]
2009-10-04 14:16:20 補充：
y = ln[2/(e-x^2 + 1)]
參考: Physics king
收錄日期: 2021-04-19 15:55:46
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20091004000051KK02684