✔ 最佳答案
By the law of conservation of energy,
Loss of G.P.E. = Gain of K.E.
mgh(1 - cos@) = 1/2 mv2
v = sqrt[2gh(1 - cos@)]
v = sqrt[2(10)(7.6)(1 - cos47*)]
Speed at the lowest point, v = 6.95 ms-1
At the lowest point,
T - mg = mv2 / h
T = mg + mv2 / h
T = (73)(10) + (73)(6.95)2 / 7.6
Tension, T = 1.19 X 103 N