Solve Natural log: Solve ln(x+3)=1 , for x?

ln(x + 3) = 1
(x + 3) = e^(1)
x = e - 3

Answer: x = e - 3

Sin^-1 (sin (7π / 3) = the angle whose sine is equal to the sine of 7π/3 The angle whose sine is equal to the sine of 7π/3 is obviously 7π/3 with is coterminal in the interval of 0 to 2π with 7π/3 - 2π = 7π/3 - 6π/3 = π/3

Let me solve it for you

ln(x+3)=1

x+3=e^(1) taking the ln other side it wil change to e
x=e-3<<<<<<your answer

x + 3 = e

x = e - 3

ln(x + 3) = 1
x + 3 = e^1
x = e - 3

Verify the result with a calculator:

note that lne=1, then:
ln(x+3)=lne
x+3=e
x=e-3 (e=2.72 approx.)
x= -0.28 (approx.)

( x + 3 ) = 1
x + 3 = 1
x = 1 - 3
x = - 2

X=1+(-3) (number 3 goes on the other side by diferrent sing)
therefor x=-2.

here is my solution:
(x+3)=1
x+3=1
x=1-3
x= -4 is the answer