Laws of indices:
(9(2^n)-3(2^n+1))/5(2^n-1)
F.3數學1條,緊急!!!!10點!!
2009-10-01 6:18 am
回答 (1)
2009-10-01 6:38 am
✔ 最佳答案
(9(2^n)-3(2^n+1))/5(2^n-1) = [9(2^n) - 3*2(2^n)] / [5 (2^n)/2]
= (2^n)(9 - 3*2) / [(2^n) * 5/2]
= (9 - 3*2) / (5/2)
= 3 / (5/2)
= 6/5
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