If 3+√6 and 3-√6 are the roots of x^2+rx+s=0, find ihe values of r and s.
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quadratic equation
2009-10-01 4:28 am
回答 (2)
2009-10-01 4:31 am
✔ 最佳答案
Sum of roots = 3+√6 + 3-√6 = - r/1
6 = - r
r = - 6
Product of roots = (3+√6)(3-√6) = s/1
9 - 6 = s
s = 3
2009-09-30 20:35:33 補充：
3+√6 + 3-√6
= 3 + 3 + √6 - √6
= 3 + 3
= 6
2009-10-01 10:26 am
If 3+√6 and 3-√6 are the roots of x^2+rx+s=0, find ihe values of r and s.
Sum of roots = 3+√6 + 3-√6 = -r/1
6 = -r
r = -6
Product of roots = (3+√6)(3-√6) = s/1
s = 3^2 - √6^2
= 9 - 6
s = 3
Sum of roots = 3+√6 + 3-√6 = -r/1
6 = -r
r = -6
Product of roots = (3+√6)(3-√6) = s/1
s = 3^2 - √6^2
= 9 - 6
s = 3
參考: me
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