中二簡單factorization

2009-09-29 9:01 am

factorize 2x^2(y+1)^2-4xy^2(y+1)

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回答 (3)

2009-09-30 1:28 am

✔ 最佳答案

2x^2(y+1)^2-4xy^2(y+1)

= 2x^2(y+1)(y+1)- 4xy^2 (y+1)

= 2x (y+1) (x+y+1-2y^2)

希望幫到你~

2009-09-29 17:30:04 補充：
更改: 2x (y+1) (xy+x-2y^2)

參考: ME

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2009-09-30 4:35 am

2x^2(y+1)^2-4xy^2(y+1)

=2x^2(y+1)(y+1)-4xy^2(y+1)

=(y+1)[2x^2(y+1)-4xy^2]

=(y+1)(2x^2y+2x^2-4xy^2)

=2x(y+1)(xy+x+2y^2)

參考: Me, my marker, my brain, my hand and my whiteboard

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2009-09-29 10:13 am

2x²(y + 1)² - 4xy²(y + 1)

= 2x(y + 1)[x(y + 1) - 2y²] ←← <<抽出 common factors>>

= 2x(y + 1)(xy + x - 2y²) ...... (答案)

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