1. 4^3k+1 = 4^3k + 24
2. 4^k+1 = 4(2^2k-1) + 1
Maths!!F.3(Laws of Indices)!!
2009-09-29 5:40 am
回答 (1)
2009-09-29 6:55 am
✔ 最佳答案
(1) 43k + 1 = 43k + 24(4)(43k) - 43k = 24
(3)(43k) = 24
43k = 8
(22)3k = 23
26k = 23
6k = 3
k = 1/2
(2) (4k + 1) = (4)(22k - 1) + 1
(4)(4k) = (4)(22k)/2 + 1
(4)(22)k = (2)(22k) + 1
(4)(22k) - (2)(22k) = 1
(2)(22k) = 1
22k = 1/2
22k = 2-1
2k = -1
k = -1/2
收錄日期: 2021-04-23 23:21:34
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090928000051KK01592