問題:
金的密度是水的19.3倍,一塊大小為20cmx10 cmx5 cm的金礡,它的所質量是多少?
金礡的質量
2009-09-26 9:14 pm
回答 (1)
2009-09-27 3:56 am
✔ 最佳答案
Density of gold = 19.3 x 1 g/cm3 = 19.3 g/cm3, where 1 g/cm3 is the density of water.Mass = desnity x volume = 19.3 x (20x10x5) g = 19300 g = 19.3 kg
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原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090926000051KK00728